pandas.core.groupby.SeriesGroupBy.nlargest

SeriesGroupBy.nlargest(*args, **kwargs)[source]

Return the largest n elements.

Parameters:	n : int Return this many descending sorted values keep : {‘first’, ‘last’, False}, default ‘first’ Where there are duplicate values: - first : take the first occurrence. - last : take the last occurrence. take_last : deprecated
Returns:	top_n : Series The n largest values in the Series, in sorted order

See also

Series.nsmallest

Notes

Faster than .sort_values(ascending=False).head(n) for small n relative to the size of the Series object.

Examples

>>> import pandas as pd
>>> import numpy as np
>>> s = pd.Series(np.random.randn(1e6))
>>> s.nlargest(10)  # only sorts up to the N requested